Let . We have the trivial representation , the sign representation , and the permutation representation , and its twist, as before. So we can start off the character table:
We then try , which has character as shown (sadly, this is equal to its twist by ). This is an irreducible character.
We can also try , which has character below; it isn’t irreducible.
By taking inner products with the characters we’ve already found, we see that
where is an irreducible character. We get one more from twisting .
This gives all of the irreducible characters, which we assemble into Table 2.
Find a more explicit description of the representation with character .